Wednesday, 31 March 2021

c-tutorial-conditional-if-else/problem

 if else hackerrank c++ problem

Given a positive integer , do the following:

  • If , print the lowercase English word corresponding to the number (e.g., one for two for , etc.).
  • If , print Greater than 9.

Input Format

A single integer, .

Constraints

Output Format

If , then print the lowercase English word corresponding to the number (e.g., one for two for , etc.); otherwise, print Greater than 9.

Program:

#include<iostream>
#include<string>
#include<bits/stdc++.h>
using namespace std;
int main(){
    int n;
    string a[10]={"Greater than 9""one""two""three""four""five""six""seven""eight""nine"};
    cin>>n;
    if(n>9){
        cout<<a[0]<<endl;
    }else if(0<n<=9){
        cout<<a[n]<<endl;
    }
    return 0;
}

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