c++ data type hackerrank basic data type 2nd problem

Since float has a precision of up to only 7 digits, it shows garbage values after its precision is exceeded.

Our double variable shows the correct number because it has a precision of 15 digits, while the number itself consists of 13 digits

Solution 1:

add header  library #include <bits/stdc++.h> and use fixed setprecision(n) in the code

cout<<fixed<<setprecision(3)<<d<<endl;

cout<<fixed<<setprecision(9)<<e<<endl;

Solution 2:

use printf:

printf("%.3f\n", f);

printf("%.9lf", z);

#include <iostream>

#include <cstdio>

#include <bits/stdc++.h>

using namespace std;

int main() {

    int a;

    long b;

    char c;

    float d;

    long double e;

    cin>>a>>b>>c>>d>>e;

    cout<<a<<endl;

    cout<<b<<endl;

    cout<<c<<endl;

    cout<<fixed<<setprecision(3)<<d<<endl;

    cout<<fixed<<setprecision(9)<<e<<endl;

    

    return 0;

}

or

printf("%.3f\n", f);

printf("%.9lf", z);